Former Florida Gov. Jeb Bush and former Arkansas Gov. Mike Huckabee are leading a pack of Republicans in Iowa for the GOP presidential nomination in 2016, according to a new poll. 

The survey by GOP firm Vox Populi released Tuesday shows 18 percent of active GOP voters in the early caucus state would vote for Bush, narrowly edging out Huckabee with 15 percent. 

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Huckabee and Bush have been near the top of a tight pack of potential GOP candidates for the last few months in Iowa, according to similar polling. 

Four other potential GOP presidential candidates also score double digits: Wisconsin Rep. Paul RyanPaul RyanTrump to meet Thursday with House Freedom Caucus members Healthcare fight pits Trump against Club for Growth High drama for ObamaCare vote MORE (13 percent), Kentucky Sen. Rand PaulRand PaulHealthcare fight pits Trump against Club for Growth GOP rep: Trump could be 'one-term president' if healthcare bill passes Overnight Defense: Pentagon chief urges Congress to approve budget boost | Senate fight over NATO addition MORE (12 percent), Florida Sen. Marco Rubio (11 percent), and Rick Santorum (10 percent).

Nine percent said they would vote for Texas Sen. Ted Cruz, while Wisconsin Gov. Scott Walker and New Jersey Gov. Chris Christie are tied at the bottom with 6 percent. 

On the Democratic side, 65 percent said they would vote for Hillary ClintonHillary Rodham ClintonObama and Trump haven’t talked since inauguration Perez, Ellison start multistate ‘turnaround tour’ for Dems Watergate reporter on Russia: 'I’ve been saying for a while there’s a coverup going on' MORE, who has dominated early polling and started a tour to promote her new book Tuesday. Eighteen percent would choose Vice President Biden, while 12 percent prefer Sen. Elizabeth WarrenElizabeth WarrenSenate nixes Obama-era workplace safety rule Five takeaways from Labor pick’s confirmation hearing Warren: 'No confidence' in Trump's Labor pick MORE (Mass.). 

The poll surveyed 667 active voters from June 4-5 and has a margin of error of 3.8 percent.