Democratic presidential hopeful Bernie SandersBernie SandersVoter fraud allegations reignite squabble Mulvaney vows to give Trump straight talk on entitlements Senate confirms Trump's UN ambassador MORE has overtaken primary rival Hillary ClintonHillary Rodham ClintonTrump clamps down on federal agencies Mellman: First things first? Dems indignant as Comey keeps his job MORE to hold a slight edge in Wisconsin, according to a Marquette Law School poll released on Thursday.
The Vermont senator trailed Clinton by a 9-point margin in Wisconsin, 50–41 percent, in November.
The poll also finds Sanders matching up better than Clinton against top Republicans in hypothetical general election races in the Badger State.
Sanders defeats GOP primary front-runner Donald TrumpDonald TrumpSenate committee moving forward with Russia hacking probe Trump must re-engage Africa to halt Chinese inroads Voter fraud allegations reignite squabble MORE by 20 points, 54–34 percent, while Clinton only wins by 10 points, 47–37 percent.
He also defeats Ted CruzTed CruzCruz shares 'proof' of basketball skills - with pic of Duke look-alike Cruz introduces bill letting states bar refugees Trump's America: Businessmen in, bureaucrats out MORE by an 18-point margin, 53–35, while Clinton ties the Texas senator, 43–43.
And Sanders trumps Marco RubioMarco RubioWebb: What matters now is policy McMahon dodges smackdown from Small Business Committee Why the era of US global leadership is over MORE by an identical margin, 53–35, while Clinton narrowly edges Rubio by a 44–43 margin.
Overall, in presidential head to head match-ups, Sanders does better than Clinton against the leading GOP candidates. #mulawpoll— MULawPoll (@MULawPoll) February 25, 2016
Charles Franklin, the director of the Marquette poll, said Sanders is especially strong in head-to-head matchups because he draws support from independents in the state.
The poll surveyed 343 Democratic primary voters from Feb. 18–21 and has a 6.9 percent margin of error.