Poll: Nearly 70 percent of Americans say Trump shouldn't fire Mueller
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A majority of American voters believe that President TrumpDonald John TrumpSunday shows preview: Trump sells U.N. reorganizing and Kavanaugh allegations dominate Ex-Trump staffer out at CNN amid “false and defamatory accusations” Democrats opposed to Pelosi lack challenger to topple her MORE should not fire special counsel Robert MuellerRobert Swan MuellerSasse: US should applaud choice of Mueller to lead Russia probe MORE, according to a poll released Tuesday.

A Quinnipiac University poll, conducted April 6–9, found that 69 percent of voters, including 55 percent of Republicans, oppose Trump firing Mueller. Just 13 percent of voters said they support Trump firing Mueller, according to the poll.

A little more than half  52 percent of voters said Mueller is conducting a “fair investigation." Among Republicans, 54 percent said they believe the investigation into Russian meddling in the 2016 election is not fair.


The poll results were released one day after Trump launched a series of fresh attacks against Mueller and the Department of Justice following reports that the FBI raided the office of his personal lawyer, Michael Cohen.

Federal prosecutors in Manhattan obtained a series of search warrants for the raid, which were based “in part” on a referral from Mueller’s office. Agents seized communications between Cohen and Trump, tax documents and records related to Cohen's $130,000 "hush money" payment to adult-film star Stormy Daniels.

The president called the special counsel's investigation a “witch hunt,” claimed Mueller’s team was biased and said multiple people have suggested he fire the special counsel.

“We’ll see what happens,” Trump said.

His comments sparked renewed conversation over whether Trump might order the firing of Mueller. 

Democrats and some Republicans called for legislation to be passed to protect Mueller, while most GOP lawmakers warned against firing the special counsel but said a bill to prevent his ouster would not be necessary.