Ex-Trump campaign aide Nunberg to meet with Senate Intel panel

Former Trump campaign aide Sam Nunberg is slated to meet in January with the Senate Intelligence Committee as the panel continues to investigate Russian interference in the 2016 presidential election.

Nunberg confirmed to The Washington Post that the meeting has been scheduled and said he is "happy to cooperate and appear” in front of the committee. The meeting is likely to be a closed session, according to The Post.

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Nunberg also told the newspaper that he is uncertain about what subjects he'll discuss with the committee but predicted he would answer questions about longtime Trump ally Roger StoneRoger Jason StoneJudge finds Stone violated gag order, blocks him from using social media Counterprotesters outnumber far-right extremists at DC rally Judge orders Roger Stone to file rebuttal to allegation he violated gag order MORE and the Trump campaign.

Stone has appeared at the center of special counsel Robert MuellerRobert (Bob) Swan MuellerTop Republican considered Mueller subpoena to box in Democrats Kamala Harris says her Justice Dept would have 'no choice' but to prosecute Trump for obstruction Dem committees win new powers to investigate Trump MORE's probe into Russian interference in the 2016 election because of his apparent ties to WikiLeaks in the months leading up to the election.

Mueller is thought to be looking into whether Stone or anyone else had information in advance of WikiLeaks publishing hacked Democratic emails, including those from John Podesta, Hillary ClintonHillary Diane Rodham ClintonHillary Clinton slams Trump rally: 'The time has come again' to fight for democracy Trump blasts minority Democrats, rally crowd chants 'send her back' The Memo: Democrats debate Trump response – 'Being righteous and losing sucks' MORE's campaign chairman. 

Nunberg, who in 2015 worked on Trump's presidential campaign, testified in March before a grand jury as part of Mueller's investigation after he initially said he would ignore Mueller's subpoena.